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SQL> SELECT E.*, P.* FROM EMPLOYEE E, PROJECT P; PLAN JOIN (P NATURAL,E NATURAL)

(Continues)

topic use specially scripted non-indexed versions of the Employee, Project, and Department tables, named Employee1, Project1, and Department1, respectively. A script for creating these tables, named NO_INDEXES.SQL, can be downloaded from http://www.apress.com.

22

It simply merges each stream on the left with each stream on the right. The optimizer has no use for an index. However, this example is useful for introducing the connection between table aliases in the join specification and those in the plan. The aliases specified in the query are used in the plan printed by the optimizer. When specifying a custom plan, it is a good idea to use the same mode of table identification as is used in the query, for consistency. However, whereas the SQL parser disallows mixing table identifiers and aliases in queries, the PLAN clause accepts any mixture.5 For example, the following is accepted. Note that the optimizer keeps the table identifiers consistent with those used in the query specification.

SQL> SELECT E.*, P.* FROM EMPLOYEE E, PROJECT P CON> PLAN JOIN (PROJECT NATURAL,EMPLOYEE NATURAL); PLAN JOIN (P NATURAL,E NATURAL)

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Listing 4-6. Populate the tables (literal values in SQL force parsing)

This join denormalizes a one-to-many relationship each employee has one or more salary history records:

SELECT E.*, S.OLD_SALARY, S.NEW_SALARY FROM EMPLOYEE E JOIN SALARY_HISTORY S ON S.EMP_NO = E.EMP_NO; PLAN JOIN (S NATURAL, E INDEX (RDB$PRIMARY7))

The optimizer chooses to loop over the (potentially) longer detail stream in order to search for relevant rows by the unique primary key index of the EMPLOYEE table. In this instance, either the number of rows in each table is roughly equal, or the number of rows in SALARY_HISTORY does not exceed the number of rows in EMPLOYEE sufficiently to outweigh the benefit of using the unique index as the lookup key. This is an inner join and the optimizer reasonably guesses that the right stream will determine the length of the river. Let s look at the optimizer s treatment of the same streams, when the join is left outer:

Figure 3-1. Viewing the current list of users Click the Add New Person link at the bottom of this screen to add a new user. This opens up a blank form that you can fill in to create the new user account. You need to provide 13 pieces of information to create a new user: The full name of the user. This is the name that FogBugz will display throughout the application. The e-mail address for the user. If the user has more than one e-mail address, and they want all FogBugz e-mail sent to all of their addresses, enter them separated by commas. The type of user: normal, administrator, community, or virtual. I ll discuss user types further in the next section of the chapter. Whether this particular user is active. Your license count limits the number of active users you have, but you can also have any number of inactive users who can t log on. You ll almost always want new users to be active when you first create them, unless you re preparing for new licenses that you haven t purchased yet. The user s homepage on the Web. This will appear as a hyperlink on the user s name in discussion group postings. The user s phone number. This is displayed on the user list in case someone needs to contact the user outside of the system for more information.

Querying Multiple Tables LEFT JOIN SALARY_HISTORY S ON S.EMP_NO = E.EMP_NO; PLAN JOIN (E NATURAL, S INDEX (RDB$FOREIGN21))

BEGIN FOR i IN 1..10000 LOOP EXECUTE IMMEDIATE 'INSERT INTO test_nocons VALUES ('||i ||',RPAD(TO_CHAR('||i ||'),11,''.'')' ... ||',RPAD(TO_CHAR('||i ||'),30,''.''))'; END LOOP; COMMIT; END; / The results are shown in Table 4-10. Table 4-10. Results of the Second Test

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